Uji Kompetensi Bab 6, Romawi 2, no.22

A.      D₁ = m_a =  50 gr

                   T_air = 100 ⁰ C

                   Menjadi uap air 100 ⁰ C

          D₂ =  Q . . . ?

          D₃ = Q  = m_a . k_u

                        = 50 . 540

                        = 27000 kal

 

      B.     D₁ =       m_u         =       20 gr

                   T_uap = 100 ⁰ C

                                T_air = 50 ⁰ C

          D₂ =  Q . . . ?

          D₃ = Q  = m_a . k_c + m_{u .} C_{a .} Δt

                        = 20 . 540 + 20 . 1 (100-50)

                        = 10800 + 1000

                        = 11800 kal

By: Vincent Sidharto / XJ - 37