Uji Kompetensi Bab 7, Romawi 2, no.25

I1+I2=I3

Loop 1                                                             Loop2

ΣE + ΣIR = 0                                                 ΣE + ΣIR = 0

-6+3I1+3I3=0                                                -6+6I2+3I3 = 0

6I1+3I2=6                                                      9I2+3I1=6

 

6I1+3I2=6

6I1+18I2=12  -

-------------

     -15I2=-6

     I2=2:5=0,4A

 

6I1+3.2/5=6

6I1=6-6/5

I1=4/5A

 

I3=6/5A

a.Hambatan 2Ω        I1=4/5A

b.Hambatan 3Ω        I3=6/5A

c.Hambatan 5Ω        I2=2/5A

 

By: Steve Suryadinata / XJ - 35