Uji Kompetensi Bab 6, no,3

Diket: 

T_bx: 15^oX

T_dx: 165^oX

T₁ : 42^oX

Ditanya: 

T₂

Jawab: 

(T₁-T_bx)/(T_dx-T_bx)  =  (T₂-T_bcelcius)/(T_dcelcius-T_bcelcius)

(42-15)/(165-15)  = (T₂-0)/(100-0)

27/150 =  T₂/100

2700                           = 50T₂

T₂ = 18 ^oC

By: Anita Adelia W. / XJ - 06