Uji Kompetensi Bab 7, no.29

Diket : 

m_air: 1 liter = 1 kg

T₁ : 20^oC

T₂ : 100^oC

∆T : 80 ^oC

 t : 5 menit = 300 detik

V : 220 volt

C_air : 4200 joule/kg^oC

µ : 80%

                

Ditanya: 

R

Jawab :

µ . P . t = Q

µ . V²/R . t = m . ∆T . c

80/100 . (220)²/R . 300 = 1 . 80 . 4200

11616000 / R = 336000

R = 34,57 ohm 

By: Anita Adelia W. / XJ - 06